# 	**Example 6.2: Porosity and Water Content**

#Given
Vs = 75 cm^3
Ms = 150.79 g
Msat = 153.67 g
Mdry = 126.34 g
rho = 0.998 g/cm^3

#Part A
n = 100*((Msat-Mdry)/rho)/Vs    #Fetter 36.5%

#Part B
thetag = 100 * (Ms-Mdry)/Mdry   #Fetter 19.28%

#Part C
thetav = ((Ms-Mdry)/rho)/Vs     #Fetter 0.325

#Part D
Rs = ((Ms-Mdry)/rho)/((Msat-Mdry)/rho)   #Fetter 0.891

#Part E
rb = Mdry/Vs; g/cm^3    #Fetter 1.68 g/cm^3

#Part F
rm = Mdry/(Vs - ((Msat-Mdry)/rho) ); g/cm^3   #Fetter 2.65 g/cm^3

#Part G
n = 100*(1-rb/rm)    #Fetter 36.6%




# Homework Problems:

TBD